Solve the Equation $\log 2 \mathrm{x}=\log 4+\log (\mathrm{x}-3)$ A) $\{-6\}$ B) $\{6\}$ C) $\{1\}$

Solve the equation.
- $\log 2 \mathrm{x}=\log 4+\log (\mathrm{x}-3)$

A) $\{-6\}$
B) $\{6\}$
C) $\{1\}$
D) $\{-2\}$