Solve the problem.
-Use the formula $L=10 \cdot \log \frac{I}{I_{0}}$, where the loudness of a sound in decibels is determined by $I$, the number of watts per square meter produced by the sound wave, and $\mathrm{I}_{0}=10^{-12}$ watts per square meter. What is the intensity of a noise measured at $93 \mathrm{db}$ ?
A) $1.09 \times 10^{16}$ watts per square meter
B) $2 \times 10^{-2}$ watts per square meter
C) $9.3 \times 10^{-10}$ watts per square meter
D) $2 \times 10^{-3}$ watts per square meter

Question

Quizplus · Accepted Answer

To find the intensity $I$, rearrange the formula: $I = I_0 \times 10^{L/10}$. Substituting $L = 93$ and $I_0 = 10^{-12}$, we get $I = 10^{-12} \times 10^{9.3} = 2 \times 10^{-3}$ watts per square meter.

Solve the Problem L=10⋅log⁡II0L=10 \cdot \log \frac{I}{I_{0}}L=10⋅logI0​I​ , Where the Loudness of a Sound in Decibels Is

Solve the Problem $L=10 \cdot \log \frac{I}{I_{0}}$ , Where the Loudness of a Sound in Decibels Is