Which of the following is a piecewise defined function for $f(x)=\frac{|2 x|}{x}$ ? A) $f(x)= \begin{cases}-2, & x0\end{cases}$ B) $f(x)= \begin{cases}-2, & x \leq 0 \ 2, & x0\end{cases}$ C) $f(x)=\left\{\begin{array}{cc}-2, & x0\end{array}\right.$ D)$f(x)= \begin{cases}-\frac{2}{x}, & x0\end{cases}$

Question

Which of the following is a piecewise defined function for $f(x)=\frac{|2 x|}{x}$ ? A) $f(x)= \begin{cases}-2, & x<0 \ 2, & x>0\end{cases}$ B) $f(x)= \begin{cases}-2, & x \leq 0 \ 2, & x>0\end{cases}$ C) $f(x)=\left\{\begin{array}{cc}-2, & x<0 \ 0, & x=0 \ 2, & x>0\end{array}\right.$ D)$f(x)= \begin{cases}-\frac{2}{x}, & x<0 \ \frac{2}{x}, & x>0\end{cases}$

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The Answer of Which of the following is a piecewise defined function for $f(x)=\frac{|2 x|}{x}$ ? A) $f(x)= \begin{cases}-2, & x<0 \ 2, & x>0\end{cases}$ B) $f(x)= \begin{cases}-2, & x \leq 0 \ 2, & x>0\end{cases}$ C) $f(x)=\left\{\begin{array}{cc}-2, & x<0 \ 0, & x=0 \ 2, & x>0\end{array}\right.$ D)$f(x)= \begin{cases}-\frac{2}{x}, & x<0 \ \frac{2}{x}, & x>0\end{cases}$

Which of the Following Is a Piecewise Defined Function For f(x)=\frac{|2