Let $g(x)=\sqrt{16-x^{2}}$. Which of the following functions will translate the graph of $g 3$ units to the left and 6 units down?
A) $ h(x)=\sqrt{16-(x-3)^{2}}-6$
B) $ h(x)=\sqrt{16-(x-3)^{2}}+6$
C) $ h(x)=\sqrt{16-(x+3)^{2}}-6$
D) $h(x)=\sqrt{16-(x+3)^{2}}+6$

Question

Quizplus · Accepted Answer

Translating 3 units to the left involves replacing $x$ with $x+3$, and translating 6 units down involves subtracting 6 from the function.

Let g(x)=16−x2g(x)=\sqrt{16-x^{2}}g(x)=16−x2​ Which of the Following Functions Will Translate the Graph

Let $g(x)=\sqrt{16-x^{2}}$ Which of the Following Functions Will Translate the Graph