Does $\frac{\log A^{4}-\log \sqrt{A}}{\log \left(e^{\ln e}\right)}=\frac{7}{2} \frac{\log A}{\log e}$ ?

Name: Does $\frac{\log A^{4}-\log \sqrt{A}}{\log \left(e^{\ln e}\right)}=\frac{7}{2} \frac{\log A}{\log e}$ ?
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Question

Quizplus · Accepted Answer

The expression simplifies to $\frac{7}{2} \frac{\log A}{\log e}$ by using logarithmic identities: $\log A^4 = 4\log A$, $\log \sqrt{A} = \frac{1}{2}\log A$, and $\log(e^{\ln e}) = \ln e = 1$.

Does log⁡A4−log⁡Alog⁡(eln⁡e)=72log⁡Alog⁡e\frac{\log A^{4}-\log \sqrt{A}}{\log \left(e^{\ln e}\right)}=\frac{7}{2} \frac{\log A}{\log e}log(elne)logA4−logA​​=27​logelogA​

Does $\frac{\log A^{4}-\log \sqrt{A}}{\log \left(e^{\ln e}\right)}=\frac{7}{2} \frac{\log A}{\log e}$