The point $(a, b)$ lies on the graph of $y=f(x)$. If the graph is reflected across the $y$-axis and compressed toward the $y$-axis by a factor of $d$ (with $d

Question

The point $(a, b)$ lies on the graph of $y=f(x)$. If the graph is reflected across the $y$-axis and compressed toward the $y$-axis by a factor of $d$ (with $d<1$ ), and then translated upward 4 units, what are the new coordinates for the point $(a, b)$ ?
A) $(d(a+4), 4+b)$
B) $(-d a+4, b+4)$
C) $(d a, b+4)$
D) $(-d a, b+4)$

Quizplus · Accepted Answer

Reflecting across the y-axis changes the x-coordinate to its negative. Compressing toward the y-axis by a factor of d multiplies the x-coordinate by d. Translating upward by 4 units adds 4 to the y-coordinate. Thus, the new coordinates are $(-d a, b+4)$.

The Point (a,b)(a, b)(a,b) Lies on the Graph Of y=f(x)y=f(x)y=f(x) If the Graph Is Reflected Across The Of y=f(x)

The Point $(a, b)$ Lies on the Graph Of $y=f(x)$ If the Graph Is Reflected Across The Of y=f(x)