The volume of pollutants (in millions of cubic feet) in a certain reservoir is given by $P(t)=370+25 t$, where $t$ is time in years. The volume of the reservoir (including pollutants) is gradually increasing and is given by $R(t)=11,000+130 t$. Let $C(t)$ be the fraction of the reservoir's volume that consists of pollutants. What percent of the reservoir's total volume consisted of pollutants in the year $t=0$ ? Round to 1 decimal place.

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The Answer of The volume of pollutants (in millions of cubic feet) in a certain reservoir is given by $P(t)=370+25 t$, where $t$ is time in years. The volume of the reservoir (including pollutants) is gradually increasing and is given by $R(t)=11,000+130 t$. Let $C(t)$ be the fraction of the reservoir's volume that consists of pollutants. What percent of the reservoir's total volume consisted of pollutants in the year $t=0$ ? Round to 1 decimal place.

The Volume of Pollutants (In Millions of Cubic Feet) in a Certain