Rewrite the equation $15 x^{2}-4 y^{2}=-251+150 x-32 y$ in the form $\frac{(x-h)^{2}}{a^{2}}-\frac{(y-k)^{2}}{b^{2}}=1$ or $\frac{(y-k)^{2}}{b^{2}}-\frac{(x-h)^{2}}{a^{2}}=1$

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The Answer of Rewrite the equation $15 x^{2}-4 y^{2}=-251+150 x-32 y$ in the form $\frac{(x-h)^{2}}{a^{2}}-\frac{(y-k)^{2}}{b^{2}}=1$ or $\frac{(y-k)^{2}}{b^{2}}-\frac{(x-h)^{2}}{a^{2}}=1$

Rewrite the Equation 15x2−4y2=−251+150x−32y15 x^{2}-4 y^{2}=-251+150 x-32 y15x2−4y2=−251+150x−32y In the Form (x−h)2a2−(y−k)2b2=1\frac{(x-h)^{2}}{a^{2}}-\frac{(y-k)^{2}}{b^{2}}=1a2(x−h)2​−b2(y−k)2​=1

Rewrite the Equation $15 x^{2}-4 y^{2}=-251+150 x-32 y$ In the Form $\frac{(x-h)^{2}}{a^{2}}-\frac{(y-k)^{2}}{b^{2}}=1$