What is the point of intersection in the first quadrant of the curves $x^{2}+y^{2}=\frac{1}{2}$ and $x^{2}-y^{2}=\frac{1}{4} ?$ Round each coordinate to 2 decimal places.

Question

Quizplus · Accepted Answer

The Answer of What is the point of intersection in the first quadrant of the curves $x^{2}+y^{2}=\frac{1}{2}$ and $x^{2}-y^{2}=\frac{1}{4} ?$ Round each coordinate to 2 decimal places.

What Is the Point of Intersection in the First Quadrant x2+y2=12x^{2}+y^{2}=\frac{1}{2}x2+y2=21​

What Is the Point of Intersection in the First Quadrant $x^{2}+y^{2}=\frac{1}{2}$