Solve the problem.
-Joe has a collection of nickels and dimes that is worth $\$ 5.00$. If the number of dimes were doubled and the number of nickels were increased by 19 , the value of the coins would be $\$ 7.95$. How many dimes does he have?
A) 19 dimes
B) 60 dimes
C) 20 dimes
D) 10 dimes

Question

Quizplus · Accepted Answer

Let the number of nickels be $n$ and the number of dimes be $d$. The value of the nickels is $0.05n$ dollars and the value of the dimes is $0.10d$ dollars. The first condition gives us the equation $0.05n + 0.10d = 5.00$. The second condition, after doubling the dimes and adding 19 nickels, gives us $0.05(n + 19) + 0.10(2d) = 7.95$. Simplifying the second equation gives $0.05n + 0.95 + 0.20d = 7.95$, which simplifies further to $0.05n + 0.20d = 7.00$. Subtracting the first equation from this gives $0.10d = 2.00$, leading to $d = 20$.

Solve the Problem $5.00\$ 5.00$5.00 If the Number of Dimes Were Doubled and the Dimes

Solve the Problem $\$ 5.00$ If the Number of Dimes Were Doubled and the Dimes