Solve. Provide answers in interval notation.
-$x^{2}-5 x-14 \leq 0$
A) $[-2,7]$
B) $(-\infty,-2] \cup[7, \infty)$
C) $(-\infty,-2]$
D) $[7, \infty)$

Question

Quizplus · Accepted Answer

To solve the quadratic inequality $x^{2}-5x-14 \leq 0$, first factor the quadratic equation: $(x-7)(x+2) \leq 0$. The roots are $x = 7$ and $x = -2$. The inequality is satisfied between these two roots, including the roots themselves, hence the solution in interval notation is $[-2, 7]$.

Solve Provide Answers in Interval Notation x2−5x−14≤0x^{2}-5 x-14 \leq 0x2−5x−14≤0 A) [−2,7][-2,7][−2,7]

Solve Provide Answers in Interval Notation $x^{2}-5 x-14 \leq 0$ A) $[-2,7]$