Solve.
-Alan's yard is rectangular and measures 13.3 meters by 8.8 meters. Maria's yard is rectangular and measures 42.2 meters by 27.5 meters. How much greater is the area of Maria's yard than the area of Alan's yard?
A) $10,434.6 \mathrm{~m}^{2}$
B) $47.6 \mathrm{~m}^{2}$
C) $1277.54 \mathrm{~m}^{2}$
D) $1043.46 \mathrm{~m}^{2}$

Question

Quizplus · Accepted Answer

The area of Alan's yard is $13.3 \times 8.8 = 117.04 \mathrm{~m}^{2}$. The area of Maria's yard is $42.2 \times 27.5 = 1160.5 \mathrm{~m}^{2}$. The difference is $1160.5 - 117.04 = 1043.46 \mathrm{~m}^{2}$.

Solve -Alan's Yard Is Rectangular and Measures 13 10,434.6 m210,434.6 \mathrm{~m}^{2}10,434.6 m2 B) 47.6 m247.6 \mathrm{~m}^{2}47.6 m2

Solve
-Alan's Yard Is Rectangular and Measures 13 $10,434.6 \mathrm{~m}^{2}$ B) $47.6 \mathrm{~m}^{2}$