Solve area problem.
-A rectangular sheet of paper is $54 \mathrm{in}$. by $39 \mathrm{in}$. An area in the shape of a parallelogram with a height of $11 \mathrm{in}$. and a base of $22 \mathrm{in}$. is cut from the paper. How much paper is left over?
A) $1985 \mathrm{in}^{2}$
B) $1864 \mathrm{in}^{2}$
C) 896 in $^{2}$
D) 2348 in $^{2}$

Question

Quizplus · Accepted Answer

The area of the rectangular sheet is $54 \times 39 = 2106 \mathrm{in}^{2}$. The area of the parallelogram is $11 \times 22 = 242 \mathrm{in}^{2}$. Subtracting the area of the parallelogram from the area of the rectangle gives the area of the paper left over: $2106 - 242 = 1864 \mathrm{in}^{2}$.

Solve Area Problem 54in54 \mathrm{in}54in By Problem 39in39 \mathrm{in}39in an Area in the Shape of a Parallelogram with \mathrm{in}

Solve Area Problem $54 \mathrm{in}$ By Problem $39 \mathrm{in}$ an Area in the Shape of a Parallelogram with \mathrm{in}