Use a proportion to solve the problem. Round to the nearest tenth as needed.
-A triangle drawn on a map has sides of lengths $8 \mathrm{~cm}, 12 \mathrm{~cm}$, and $15 \mathrm{~cm}$. The shortest of the corresponding real-life distances is $108 \mathrm{~km}$. Find the longest of the real-life distances.
A) $212.5 \mathrm{~km}$
B) $202.5 \mathrm{~km}$
C) $152.0 \mathrm{~km}$
D) $162.0 \mathrm{~km}$

Question

Quizplus · Accepted Answer

The proportion based on the shortest side (8 cm on the map) to the real-life distance (108 km) can be used to find the longest real-life distance corresponding to the 15 cm side on the map. The ratio is $8 \mathrm{~cm} : 108 \mathrm{~km} = 15 \mathrm{~cm} : x \mathrm{~km}$, solving for $x$ gives $x = \frac{15 \times 108}{8} = 202.5 \mathrm{~km}$.

Use a Proportion to Solve the Problem 8 cm,12 cm8 \mathrm{~cm}, 12 \mathrm{~cm}8 cm,12 cm

Use a Proportion to Solve the Problem $8 \mathrm{~cm}, 12 \mathrm{~cm}$