Solve the problem.
-Find $g(a+1)$ when $g(x)=\frac{1}{4} x-1$.
A) $\frac{a+3}{4}$
B) $\frac{1}{4} \mathrm{a}-4$
C) $\frac{1}{4} \mathrm{a}-1$
D) $\frac{a-3}{4}$

Name: Solve the problem. -Find $g(a+1)$ when $g(x)=\frac{1}{4} x-1$. A) $\frac{a+3}{4}$ B) $\frac{1}{4} \mathrm{a}-4$ C) $\frac{1}{4} \mathrm{a}-1$ D) $\frac{a-3}{4}$
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The Answer of Solve the problem.
-Find $g(a+1)$ when $g(x)=\frac{1}{4} x-1$.
A) $\frac{a+3}{4}$
B) $\frac{1}{4} \mathrm{a}-4$
C) $\frac{1}{4} \mathrm{a}-1$
D) $\frac{a-3}{4}$

Solve the Problem g(a+1)g(a+1)g(a+1) When g(x)=14x−1g(x)=\frac{1}{4} x-1g(x)=41​x−1 A) a+34\frac{a+3}{4}4a+3​ B) 14a−4\frac{1}{4} \mathrm{a}-441​a−4 C) 14a−1\frac{1}{4} \mathrm{a}-141​a−1

Solve the Problem $g(a+1)$ When $g(x)=\frac{1}{4} x-1$
A) $\frac{a+3}{4}$ B) $\frac{1}{4} \mathrm{a}-4$ C) $\frac{1}{4} \mathrm{a}-1$