Solve by any method. Assume $a$ and $b$ represent nonzero constants.
-$4 a x+3 y=1$
$y=2 a x$

A) $\left\{\left(\frac{1}{10 a}, \frac{1}{5}\right)\right\}$

B) $\left\{\left\{\left(\frac{1}{5}, \frac{1}{10 a}\right)\right\}\right.$

C) $\left\{\left(\frac{\mathrm{a}}{10}, \frac{1}{5}\right)\right\}$

D) $\left\{\left(\frac{1}{10}, \frac{1}{5}\right)\right\}$

Question

Solve by any method. Assume $a$ and $b$ represent nonzero constants.
-$4 a x+3 y=1$
$y=2 a x$

A) $\left\{\left(\frac{1}{10 a}, \frac{1}{5}\right)\right\}$

B) $\left\{\left\{\left(\frac{1}{5}, \frac{1}{10 a}\right)\right\}\right.$

C) $\left\{\left(\frac{\mathrm{a}}{10}, \frac{1}{5}\right)\right\}$

D) $\left\{\left(\frac{1}{10}, \frac{1}{5}\right)\right\}$

Quizplus · Accepted Answer

Substitute $y=2ax$ into $4ax+3y=1$, getting $4ax+3(2ax)=1$, which simplifies to $10ax=1$. Solving for $x$ gives $x=\frac{1}{10a}$. Substituting $x=\frac{1}{10a}$ into $y=2ax$ gives $y=\frac{2a}{10a}=\frac{1}{5}$. Thus, the solution is $\left(\frac{1}{10a}, \frac{1}{5}\right)$.

Solve by Any Method aaa And bbb Represent Nonzero Constants 4ax+3y=14 a x+3 y=14ax+3y=1

Solve by Any Method $a$ And $b$ Represent Nonzero Constants $4 a x+3 y=1$