How many liters (L) of a $40 \%$ alcohol solution must be mixed with $60 \mathrm{~L}$ of a $60 \%$ solution to get a $50 \%$ solution?
A) $120 \mathrm{~L}$
B) $60 \mathrm{~L}$
C) $12 \mathrm{~L}$
D) $6 \mathrm{~L}$

Question

Quizplus · Accepted Answer

To achieve a $50\%$ solution when mixing a $40\%$ solution with a $60\%$ solution, equal amounts of each must be mixed. Therefore, $60 \mathrm{~L}$ of the $40\%$ solution is needed to match the $60 \mathrm{~L}$ of the $60\%$ solution.

How Many Liters (L) of A 40%40 \%40% Alcohol Solution Must Be Mixed With

How Many Liters (L) of A $40 \%$ Alcohol Solution Must Be Mixed With