The polynomial $0.0038 x^{3}-0.003 x^{2}+0.131 x+1.43$ gives the approximate total earnings of a company, in millions of dollars, where $x=0$ corresponds to $1996, x=1$ corresponds to 1997 , and so on. This model is valid for the years from 1996 to 2000. Determine the earnings for 1999. Round your answer to the nearest hundredth million.
A) $\$ 2.15$ million
B) $\$ 1.71$ million
C) $\$ 1.95$ million
D) $\$ 1.9$ million

Question

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The Answer of The polynomial $0.0038 x^{3}-0.003 x^{2}+0.131 x+1.43$ gives the approximate total earnings of a company, in millions of dollars, where $x=0$ corresponds to $1996, x=1$ corresponds to 1997 , and so on. This model is valid for the years from 1996 to 2000. Determine the earnings for 1999. Round your answer to the nearest hundredth million.
A) $\$ 2.15$ million
B) $\$ 1.71$ million
C) $\$ 1.95$ million
D) $\$ 1.9$ million

The Polynomial 0.0038x3−0.003x2+0.131x+1.430.0038 x^{3}-0.003 x^{2}+0.131 x+1.430.0038x3−0.003x2+0.131x+1.43 Gives the Approximate Total Earnings of a Company, in Millions

The Polynomial $0.0038 x^{3}-0.003 x^{2}+0.131 x+1.43$ Gives the Approximate Total Earnings of a Company, in Millions