Find the product
-$(n-9)(n+9)$

A) $n^{2}-18 n+81$
B) $n^{2}-18$
C) $n^{2}-81$
D) $n^{2}-18 n-81$

Name: Find the product -$(n-9)(n+9)$ A) $n^{2}-18 n+81$ B) $n^{2}-18$ C) $n^{2}-81$ D) $n^{2}-18 n-81$
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Question

Find the product
-$(n-9)(n+9)$

A) $n^{2}-18 n+81$
B) $n^{2}-18$
C) $n^{2}-81$
D) $n^{2}-18 n-81$

Quizplus · Accepted Answer

This is a difference of squares problem, which follows the formula $a^2 - b^2 = (a - b)(a + b)$. Here, $a = n$ and $b = 9$, so the product is $n^2 - 9^2 = n^2 - 81$.

Find the Product - (n−9)(n+9)(n-9)(n+9)(n−9)(n+9) A) n2−18n+81n^{2}-18 n+81n2−18n+81 B) n2−18n^{2}-18n2−18 C) n2−81n^{2}-81n2−81 D) n2−18n−81n^{2}-18 n-81n2−18n−81

Find the Product
- $(n-9)(n+9)$ A) $n^{2}-18 n+81$ B) $n^{2}-18$ C) $n^{2}-81$ D) $n^{2}-18 n-81$