$(3 x-8 y)^{2}$
A) $9 x^{2}+64 y^{2}$
B) $9 x^{2}-48 x y+64 y^{2}$
C) $3 x^{2}+64 y^{2}$
D) $3 x^{2}-48 x y+64 y^{2}$

Name: $(3 x-8 y)^{2}$ A) $9 x^{2}+64 y^{2}$ B) $9 x^{2}-48 x y+64 y^{2}$ C) $3 x^{2}+64 y^{2}$ D) $3 x^{2}-48 x y+64 y^{2}$
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Question

Quizplus · Accepted Answer

This is a case of squaring a binomial, which follows the formula $(a - b)^2 = a^2 - 2ab + b^2$. Applying this to $(3x - 8y)^2$, we get $9x^2 - 2*(3x)*(8y) + 64y^2$, which simplifies to $9x^2 - 48xy + 64y^2$.

(3x−8y)2(3 x-8 y)^{2}(3x−8y)2 A) 9x2+64y29 x^{2}+64 y^{2}9x2+64y2 B) 9x2−48xy+64y29 x^{2}-48 x y+64 y^{2}9x2−48xy+64y2

$(3 x-8 y)^{2}$ A) $9 x^{2}+64 y^{2}$ B) $9 x^{2}-48 x y+64 y^{2}$