Solve for the indicated variable.
-$A=\frac{h(B+b)}{2}$ for $b$

A) $b=\frac{2 A+B h}{h}$

B) $b=\frac{A-B h}{h}$

C) $b=2 A-B h$

D) $b=\frac{2 A-B h}{h}$

Question

Solve for the indicated variable.
-$A=\frac{h(B+b)}{2}$ for $b$

A) $b=\frac{2 A+B h}{h}$

B) $b=\frac{A-B h}{h}$

C) $b=2 A-B h$

D) $b=\frac{2 A-B h}{h}$

Quizplus · Accepted Answer

To solve for $b$, we start with the given equation $A=\frac{h(B+b)}{2}$. Multiplying both sides by 2 to eliminate the denominator gives $2A = h(B+b)$. Then, we isolate $b$ by subtracting $hB$ from both sides, resulting in $2A - hB = hb$. Finally, dividing both sides by $h$ gives $b = \frac{2A - hB}{h}$, which matches choice D.

Solve for the Indicated Variable A=h(B+b)2A=\frac{h(B+b)}{2}A=2h(B+b)​ For bbb A) b=2A+Bhhb=\frac{2 A+B h}{h}b=h2A+Bh​ B) b=A−Bhhb=\frac{A-B h}{h}b=hA−Bh​

Solve for the Indicated Variable $A=\frac{h(B+b)}{2}$ For $b$ A) $b=\frac{2 A+B h}{h}$ B) $b=\frac{A-B h}{h}$