The Length a Spring Is Stretched from Its Natural Length $$\mathrm{L}=\sqrt{\frac{2 \mathrm{~W}}{\mathrm{k}}}$$

The length a spring is stretched from its natural length with work, W foot-pounds, is given by
$$\mathrm{L}=\sqrt{\frac{2 \mathrm{~W}}{\mathrm{k}}}$$
Where $\mathrm{k}$ is a constant for the given spring. If a certain spring has a constant of 74.8, and the spring is to be stretched 1.9 feet from its natural length, how much work will be necessary? Round your answer to the nearest tenth.

A) 51.6 foot-pounds
B) 135 foot-pounds
C) 270 foot-pounds
D) 71.1 foot-pounds