Use the square root property to solve the equation.
-$(x+9)^{2}-6=0$
A) $\{-9+\mathrm{i} \sqrt{6},-9-\mathrm{i} \sqrt{6}\}$
B) $\{-3,15\}$
C) $\{-3+\sqrt{6},-3-\sqrt{6}\}$
D) $\{-9+\sqrt{6},-9-\sqrt{6}\}$

Question

Quizplus · Accepted Answer

First, add 6 to both sides to isolate the squared term: $(x+9)^2 = 6$. Then, take the square root of both sides: $x+9 = \pm\sqrt{6}$. Finally, subtract 9 from both sides to solve for x, resulting in $x = -9 \pm \sqrt{6}$.

Use the Square Root Property to Solve the Equation (x+9)2−6=0(x+9)^{2}-6=0(x+9)2−6=0 A) {−9+i6,−9−i6}\{-9+\mathrm{i} \sqrt{6},-9-\mathrm{i} \sqrt{6}\}{−9+i6​,−9−i6​}

Use the Square Root Property to Solve the Equation $(x+9)^{2}-6=0$ A) $\{-9+\mathrm{i} \sqrt{6},-9-\mathrm{i} \sqrt{6}\}$