Solve the equation by completing the square.
-$a^{2}+8 a-33=0$
A) $\{-22,-11\}$
B) $\{3,-11\}$
C) $\{6,-6\}$
D) $\{-3,11\}$

Question

Quizplus · Accepted Answer

To complete the square, rewrite the equation as $a^2 + 8a = 33$. Add and subtract $(8/2)^2 = 16$ to the left side: $a^2 + 8a + 16 = 33 + 16$. This becomes $(a + 4)^2 = 49$. Taking the square root gives $a + 4 = \pm 7$. Solving for $a$, we get $a = 3$ or $a = -11$.

Solve the Equation by Completing the Square a2+8a−33=0a^{2}+8 a-33=0a2+8a−33=0 A) {−22,−11}\{-22,-11\}{−22,−11} B) {3,−11}\{3,-11\}{3,−11}

Solve the Equation by Completing the Square $a^{2}+8 a-33=0$ A) $\{-22,-11\}$ B) $\{3,-11\}$