$\frac{\mathrm{k}}{3-\mathrm{k}}-\frac{6}{\mathrm{k}}=3$

A) $\left\{\frac{-3+3 \sqrt{33}}{8}, \frac{-3-3 \sqrt{33}}{8}\right\}$

B) $\left\{\frac{3+3 \sqrt{33}}{8}\right\}$

C) $\left\{\frac{15+3 \sqrt{33}}{4}, \frac{15-3 \sqrt{33}}{4}\right\}$

D) $\left\{\frac{3+3 \sqrt{33}}{8}, \frac{3-3 \sqrt{33}}{8}\right\}$

Question

$\frac{\mathrm{k}}{3-\mathrm{k}}-\frac{6}{\mathrm{k}}=3$

A) $\left\{\frac{-3+3 \sqrt{33}}{8}, \frac{-3-3 \sqrt{33}}{8}\right\}$

B) $\left\{\frac{3+3 \sqrt{33}}{8}\right\}$

C) $\left\{\frac{15+3 \sqrt{33}}{4}, \frac{15-3 \sqrt{33}}{4}\right\}$

D) $\left\{\frac{3+3 \sqrt{33}}{8}, \frac{3-3 \sqrt{33}}{8}\right\}$

Quizplus · Accepted Answer

The equation can be solved by finding a common denominator and simplifying, leading to a quadratic equation. Solving this quadratic equation gives the solutions $\frac{3+3 \sqrt{33}}{8}$ and $\frac{3-3 \sqrt{33}}{8}$.