Solve the problem. Round your answer to the nearest tenth, when appropriate.
-The position of an object moving in a straight line is given by $s(t)=2 t^{2}-3 t$, where $s$ is in meters and $t$ is the time in seconds the object has been in motion. How long will it take the object to move $13 \mathrm{~m}$ ?
A) $3.4 \mathrm{sec}$
B) $14.0 \mathrm{sec}$
C) $29.9 \mathrm{sec}$
D) $3.2 \mathrm{sec}$

Question

Quizplus · Accepted Answer

To find the time it takes for the object to move 13 meters, set $s(t) = 13$ and solve for $t$: $2t^2 - 3t = 13$. Rearranging gives $2t^2 - 3t - 13 = 0$. Solving this quadratic equation using the quadratic formula, $t = \frac{-(-3) \pm \sqrt{(-3)^2 - 4(2)(-13)}}{2(2)}$, yields two solutions. The positive solution, which is physically meaningful in this context, is approximately $3.4$ seconds.

Solve the Problem s(t)=2t2−3ts(t)=2 t^{2}-3 ts(t)=2t2−3t , Where sss Is in Meters And

Solve the Problem $s(t)=2 t^{2}-3 t$ , Where $s$ Is in Meters And