The number of bacteria growing in an incubation culture increases with time according to $B(x)=8800(4)^{x}$, where $x$ is time in days. After how many days will the number of bacteria in the culture be 563,200 ?(Hint: Let $B(x)=563,200$.)
A) 6 days
B) 10 days
C) 1 day
D) 3 days

Question

Quizplus · Accepted Answer

To find the number of days ($x$) when the bacteria count reaches 563,200, we set $B(x) = 563,200$ and solve for $x$:$$563,200 = 8800(4)^x$$$$64 = 4^x$$$$4^3 = 4^x$$Therefore, $x = 3$ days.

The Number of Bacteria Growing in an Incubation Culture Increases B(x)=8800(4)xB(x)=8800(4)^{x}B(x)=8800(4)x

The Number of Bacteria Growing in an Incubation Culture Increases $B(x)=8800(4)^{x}$