Write in exponential form.
-$\log _{3}\left(3^{7}\right)=x$
A) $\left\{7^{3}\right\}$
B) $\left\{3^{7}\right\}$
C)$ \{3\}$
D) $\{7\}$

Name: Write in exponential form. -$\log _{3}\left(3^{7}\right)=x$ A) $\left\{7^{3}\right\}$ B) $\left\{3^{7}\right\}$ C)$ \{3\}$ D) $\{7\}$
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Quizplus · Accepted Answer

The equation $\log _{3}\left(3^{7}\right)=x$ simplifies to $x=7$ because the base of the logarithm and the base of the exponent are the same, thus they cancel each other out, leaving $x=7$.

Write in Exponential Form log⁡3(37)=x\log _{3}\left(3^{7}\right)=xlog3​(37)=x A) {73}\left\{7^{3}\right\}{73} B) {37}\left\{3^{7}\right\}{37} C) {3} \{3\}{3} D) {7}\{7\}{7}

Write in Exponential Form $\log _{3}\left(3^{7}\right)=x$ A) $\left\{7^{3}\right\}$ B) $\left\{3^{7}\right\}$ C) $\{3\}$ D) $\{7\}$