Find the equation of a circle satisfying the given conditions.
-Center: $(10,0)$; radius: $\sqrt{13}$
A) $x^{2}+(y+10)^{2}=169$
B) $(x+10)^{2}+y^{2}=13$
C) $x^{2}+(y-10)^{2}=169$
D) $(x-10)^{2}+y^{2}=13$

Question

Quizplus · Accepted Answer

The general equation of a circle with center $(h, k)$ and radius $r$ is $(x-h)^{2}+(y-k)^{2}=r^{2}$. Given the center $(10,0)$ and radius $\sqrt{13}$, the equation becomes $(x-10)^{2}+y^{2}=13$.

Find the Equation of a Circle Satisfying the Given Conditions (10,0)(10,0)(10,0)

Find the Equation of a Circle Satisfying the Given Conditions $(10,0)$