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Graph the Hyperbola with Center Shifted Away from the Origin $\frac{(x+3)^{2}}{25}-\frac{(y-3)^{2}}{16}=1$

Question 94

Multiple Choice

Graph the hyperbola with center shifted away from the origin.
- $\frac{(x+3) ^{2}}{25}-\frac{(y-3) ^{2}}{16}=1$
$Graph the hyperbola with center shifted away from the origin. - \frac{(x+3) ^{2}}{25}-\frac{(y-3) ^{2}}{16}=1 A) B) C) D)$

A)
$Graph the hyperbola with center shifted away from the origin. - \frac{(x+3) ^{2}}{25}-\frac{(y-3) ^{2}}{16}=1 A) B) C) D)$
B)
$Graph the hyperbola with center shifted away from the origin. - \frac{(x+3) ^{2}}{25}-\frac{(y-3) ^{2}}{16}=1 A) B) C) D)$
C)
$Graph the hyperbola with center shifted away from the origin. - \frac{(x+3) ^{2}}{25}-\frac{(y-3) ^{2}}{16}=1 A) B) C) D)$
D)
$Graph the hyperbola with center shifted away from the origin. - \frac{(x+3) ^{2}}{25}-\frac{(y-3) ^{2}}{16}=1 A) B) C) D)$