Solve the problem by using a nonlinear system.
-Find the dimensions of a rectangular enclosure with perimeter $40 \mathrm{yd}$ and area $75 \mathrm{yd}^{2}$.
A) $5 \mathrm{yd}$ by $15 \mathrm{yd}$
B) $6 \mathrm{yd}$ by $15 \mathrm{yd}$
C) $6 \mathrm{yd}$ by $14 \mathrm{yd}$
D) $5 \mathrm{yd}$ by $14 \mathrm{yd}$

Question

Quizplus · Accepted Answer

The dimensions that satisfy both the perimeter and area conditions are $5 \mathrm{yd}$ by $15 \mathrm{yd}$. The perimeter equation is $2l + 2w = 40$, and the area equation is $lw = 75$. Solving this system, $l = 5$ and $w = 15$ (or vice versa) are the dimensions that meet both criteria.

Solve the Problem by Using a Nonlinear System 40yd40 \mathrm{yd}40yd And Area

Solve the Problem by Using a Nonlinear System $40 \mathrm{yd}$ And Area