Verbal SAT scores have approximately a normal distribution with mean equal to 500 and standard deviation equal to 100. The 95^thpercentile of z-scores is z = 1.65. What is the 95^th percentile of verbal SAT scores? A) 335 B) 500 C) 600 D) 665

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Quizplus · Accepted Answer

To find the 95th percentile of verbal SAT scores, we use the formula for converting z-scores to original scores: X = μ + zσ. Here, μ = 500, σ = 100, and z = 1.65. Plugging these values in gives X = 500 + (1.65)(100) = 500 + 165 = 665.

Verbal SAT Scores Have Approximately a Normal Distribution with Mean