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Question 6
Solve for x:y=12(cos5x) x: y=\frac{1}{2}(\cos 5 x) x:y=21(cos5x)
A) x=12cos−15yx=\frac{1}{2} \cos ^{-1} 5 yx=21cos−15y B) x=5cos−12yx=5 \cos ^{-1} 2 yx=5cos−12y C) x=15cos−12yx=\frac{1}{5} \cos ^{-1} 2 yx=51cos−12y D) x=cos−12y5x=\cos ^{-1} \frac{2 y}{5}x=cos−152y
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