The total resistance $R$ of two resistors $R_{1}$ and $R_{2}$, connected in parallel, is $\frac{R_{1} R_{2}}{R_{1}+R_{2}}$. $R_{1}$ measures $525 \Omega$ with a maximum error of $35 \Omega$. $\mathrm{R}_{2}$ measures $375 \Omega$ with a maximum error of $24 \Omega$. Use a differential to approximate the change in $\mathrm{R}$ to two significant digits.

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The Answer of The total resistance $R$ of two resistors $R_{1}$ and $R_{2}$, connected in parallel, is $\frac{R_{1} R_{2}}{R_{1}+R_{2}}$. $R_{1}$ measures $525 \Omega$ with a maximum error of $35 \Omega$. $\mathrm{R}_{2}$ measures $375 \Omega$ with a maximum error of $24 \Omega$. Use a differential to approximate the change in $\mathrm{R}$ to two significant digits.

The Total Resistance RRR Of Two Resistors R1R_{1}R1​ And R2R_{2}R2​ , Connected in Parallel, Is

The Total Resistance $R$ Of Two Resistors $R_{1}$ And $R_{2}$ , Connected in Parallel, Is