A simply-supported beam has a uniformly-distributed load. The deflection at the point $x$ metres from the left end of the beam is given by $y=\frac{\omega}{24 k}\left(L^{3} x-2 L x^{3}+x^{4}\right)$ where $L$ is the length of the beam in metres, $\omega$ is the load in $\mathrm{N} / \mathrm{m}$, and $k$ is a constant. What is the coefficient of $x$ for a 2.00 -metre beam if the load is $600\overline{0} \mathrm{~N} / \mathrm{m}$ and $k$ is $4.00 \times 10^{7}$ ?

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The Answer of A simply-supported beam has a uniformly-distributed load. The deflection at the point $x$ metres from the left end of the beam is given by $y=\frac{\omega}{24 k}\left(L^{3} x-2 L x^{3}+x^{4}\right)$ where $L$ is the length of the beam in metres, $\omega$ is the load in $\mathrm{N} / \mathrm{m}$, and $k$ is a constant. What is the coefficient of $x$ for a 2.00 -metre beam if the load is $600\overline{0} \mathrm{~N} / \mathrm{m}$ and $k$ is $4.00 \times 10^{7}$ ?

A Simply-Supported Beam Has a Uniformly-Distributed Load xxx Metres from the Left End of the Beam Is Given

A Simply-Supported Beam Has a Uniformly-Distributed Load $x$ Metres from the Left End of the Beam Is Given