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Solve for Y y′′=32cos⁡4xy^{\prime \prime}=32 \cos 4 x , Where y′=2y^{\prime}=2 At the Point

Question 65

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Solve for y: y′′=32cos⁡4xy^{\prime \prime}=32 \cos 4 x , where y′=2y^{\prime}=2 at the point (0,1)(0,1)

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