Solve the problem.
-Assume that the sales of a certain appliance dealer are approximated by a linear function. Suppose that sales were $\$ 10,500$ in 1982 and $\$ 52,500$ in 1987 . Let $x=0$ represent 1982 . Find the equation giving yearly sales $S$.
A) $S=8400 x+10,500$
B) $S=42,000 x+52,500$
C) $S=8400 x+52,500$
D) $S=42,000 x+10,500$

Question

Quizplus · Accepted Answer

The slope of the line is $(52,500 - 10,500) / (1987 - 1982) = 42,000 / 5 = 8,400$. The equation of the line is $S = 8400x + 10,500$, where $x=0$ corresponds to 1982.

Solve the Problem $10,500\$ 10,500$10,500 In 1982 And $52,500\$ 52,500$52,500 In 1987 Let

Solve the Problem $\$ 10,500$ In 1982 And $\$ 52,500$ In 1987 Let