Solve the inequality.
-Correct Computers, Inc., finds that the cost to make $x$ laptop computers is $C=3316 x+147,692$, while the revenue produced from them is $\mathrm{R}=3537 \mathrm{x}$ ( $\mathrm{C}$ and $\mathrm{R}$ are in dollars). What is the smallest whole number of computers, $x$, that must be sold for the company to show a profit?
A) $32,639,932$
B) 22
C) 669
D) $1,012,133,276$

Question

Quizplus · Accepted Answer

The profit is given by $\mathrm{P}=\mathrm{R}-\mathrm{C}$. Substituting, we get $\mathrm{P}=3537 \mathrm{x}-(3316 \mathrm{x}+147,692)=221 \mathrm{x}-147,692$. To find the smallest whole number of computers that must be sold for the company to show a profit, we solve the inequality $\mathrm{P}>0$. Solving, we get $221 \mathrm{x}-147,692>0\Rightarrow 221 \mathrm{x}>147,692\Rightarrow \mathrm{x}>669$. Therefore, the smallest whole number of computers that must be sold for the company to show a profit is 669.

Solve the Inequality xxx Laptop Computers Is C=3316x+147,692C=3316 x+147,692C=3316x+147,692 , While the Revenue Produced from Them Is

Solve the Inequality $x$ Laptop Computers Is $C=3316 x+147,692$ , While the Revenue Produced from Them Is