Solve the problem.
-A ball is thrown vertically upward at an initial speed of $54 \mathrm{ft} / \mathrm{sec}$. Its height (in feet) after $t$ seconds is given by
$$h(t)=t(54-16 t)$$
What is the height of the ball after 2.7 seconds?
A) 29.16 feet
B) 36.45 feet
C) 51.03 feet
D) 43.74 feet

Question

Quizplus · Accepted Answer

The height of the ball after 2.7 seconds is $h(2.7) = 2.7(54-16 \cdot 2.7) = 29.16$ feet.

Solve the Problem 54ft/sec54 \mathrm{ft} / \mathrm{sec}54ft/sec Its Height (In Feet) After

Solve the Problem $54 \mathrm{ft} / \mathrm{sec}$ Its Height (In Feet) After