Write in logarithmic form.
-$4^{-3}=\frac{1}{64}$
A) $-3=\log _{1 / 64} 4$
B) $\frac{1}{64}=\log _{4}-3$
C) $-3=\log _{4} \frac{1}{64}$
D) $4=\log _{-3} \frac{1}{64}$

Name: Write in logarithmic form. -$4^{-3}=\frac{1}{64}$ A) $-3=\log _{1 / 64} 4$ B) $\frac{1}{64}=\log _{4}-3$ C) $-3=\log _{4} \frac{1}{64}$ D) $4=\log _{-3} \frac{1}{64}$
Brand: Quizplus
Rating: 4.8 (35 reviews)

Question

Quizplus · Accepted Answer

The logarithmic form of $4^{-3}=\frac{1}{64}$ is $-3=\log _{4} \frac{1}{64}$, which means the power to which 4 must be raised to get $\frac{1}{64}$ is $-3$.

Write in Logarithmic Form 4−3=1644^{-3}=\frac{1}{64}4−3=641​ A) −3=log⁡1/644-3=\log _{1 / 64} 4−3=log1/64​4 B) 164=log⁡4−3\frac{1}{64}=\log _{4}-3641​=log4​−3

Write in Logarithmic Form $4^{-3}=\frac{1}{64}$ A) $-3=\log _{1 / 64} 4$ B) $\frac{1}{64}=\log _{4}-3$