Solve the problem.
-A certain noise measures 113 decibels. If the intensity is multiplied by 10 , how many decibels will the new noise measure? Use the formula $\mathrm{D}=10 \log \left(\mathrm{S} / \mathrm{S}_{0}\right)$, where $\mathrm{S}_{0}=10^{-12} \mathrm{watt} / \mathrm{m}^{2}$.
A) 123 decibels
B) 114 decibels
C) 1130 decibels
D) 113 decibels

Question

Quizplus · Accepted Answer

When the intensity is multiplied by 10, the decibel level increases by 10. Therefore, 113 + 10 = 123 decibels.

Solve the Problem D=10log⁡(S/S0)\mathrm{D}=10 \log \left(\mathrm{S} / \mathrm{S}_{0}\right)D=10log(S/S0​) , Where S0=10−12watt/m2\mathrm{S}_{0}=10^{-12} \mathrm{watt} / \mathrm{m}^{2}S0​=10−12watt/m2

Solve the Problem $\mathrm{D}=10 \log \left(\mathrm{S} / \mathrm{S}_{0}\right)$ , Where $\mathrm{S}_{0}=10^{-12} \mathrm{watt} / \mathrm{m}^{2}$