Solve the equation for $s$.
-$\log (4+r)=\log (3 s-2)$
A) $\log 3+r$
B) $\frac{3}{6+r}$
C) $\log (6+r)$
D) $\frac{6+r}{3}$

Name: Solve the equation for $s$. -$\log (4+r)=\log (3 s-2)$ A) $\log 3+r$ B) $\frac{3}{6+r}$ C) $\log (6+r)$ D) $\frac{6+r}{3}$
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Question

Quizplus · Accepted Answer

Since the logarithms are equal, the arguments must be equal: $4 + r = 3s - 2$. Solving for $s$, we get $3s = 6 + r$, so $s = \frac{6 + r}{3}$.

Solve the Equation For sss - log⁡(4+r)=log⁡(3s−2)\log (4+r)=\log (3 s-2)log(4+r)=log(3s−2) A) log⁡3+r\log 3+rlog3+r

Solve the Equation For $s$
- $\log (4+r)=\log (3 s-2)$ A) $\log 3+r$