Multiply both sides of each equation by a common denominator to eliminate the fractions. Then solve the system.
-$\frac{1}{3} x+\frac{1}{3} y=0$
$\frac{1}{3} \mathrm{x}-\frac{1}{3} \mathrm{y}=\frac{4}{3}$
A) $(1,-1)$
B) $(2,-2)$
C) $(-2,-1)$
D) No solution

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The Answer of Multiply both sides of each equation by a common denominator to eliminate the fractions. Then solve the system.
-$\frac{1}{3} x+\frac{1}{3} y=0$
$\frac{1}{3} \mathrm{x}-\frac{1}{3} \mathrm{y}=\frac{4}{3}$
A) $(1,-1)$
B) $(2,-2)$
C) $(-2,-1)$
D) No solution

Multiply Both Sides of Each Equation by a Common Denominator 13x+13y=0\frac{1}{3} x+\frac{1}{3} y=031​x+31​y=0

Multiply Both Sides of Each Equation by a Common Denominator $\frac{1}{3} x+\frac{1}{3} y=0$