Convert the objective function into a maximization function.
-Minimize $w=y_{1}+2 y_{2}+3 y_{3}$
Subject to: $4 y_{1}+3 y_{2}+y_{3} \geq 16$
$\mathrm{y}_{1}+2 \mathrm{y}_{2}+4 \mathrm{y}_{3} \geq 40$
$\mathrm{y}_{1} \geq 0, \mathrm{y}_{2} \geq 0, \mathrm{y}_{3} \geq 0$
A) Maximize $z=y_{1}+2 y_{2}+3 y_{3}-y_{4}$
B) Maximize $z=-y_{1}-2 y_{2}-4 y_{3} \leq 40$
C) Maximize $z=-4 y_{1}-3 y_{2}-y_{3} \leq 16$
D) Maximize $z=-y_{1}-2 y_{2}-3 y_{3}$

Question

Quizplus · Accepted Answer

To convert a minimization problem to a maximization problem, you take the negative of the objective function. Thus, maximizing $-w$ is equivalent to minimizing $w$.

Convert the Objective Function into a Maximization Function w=y1+2y2+3y3w=y_{1}+2 y_{2}+3 y_{3}w=y1​+2y2​+3y3​

Convert the Objective Function into a Maximization Function $w=y_{1}+2 y_{2}+3 y_{3}$