Use the two-stage method to solve.
-Find $x_{1} \geq 0$ and $x_{2} \geq 0$ such that
$$\begin{aligned}
& x_{1}+x_{2} \leq 50 \
& x_{1}+x_{2} \geq 25 \
& 2 x_{1}+x_{2} \leq 60
\end{aligned}$$
And $\mathrm{z}=3 \mathrm{x}_{1}+4 \mathrm{x}_{2}$ is maximized.
A) $x_{1}=50, x_{2}=0, z=150$
B) $x_{2}=50, x_{1}=0, z=200$
C) $x_{1}=25, x_{2}=25, z=175$
D) $x_{1}=10, x_{2}=40, z=190$

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The Answer of Use the two-stage method to solve.
-Find $x_{1} \geq 0$ and $x_{2} \geq 0$ such that
$$\begin{aligned}
& x_{1}+x_{2} \leq 50 \
& x_{1}+x_{2} \geq 25 \
& 2 x_{1}+x_{2} \leq 60
\end{aligned}$$
And $\mathrm{z}=3 \mathrm{x}_{1}+4 \mathrm{x}_{2}$ is maximized.
A) $x_{1}=50, x_{2}=0, z=150$
B) $x_{2}=50, x_{1}=0, z=200$
C) $x_{1}=25, x_{2}=25, z=175$
D) $x_{1}=10, x_{2}=40, z=190$

Use the Two-Stage Method to Solve x1≥0x_{1} \geq 0x1​≥0 And x2≥0x_{2} \geq 0x2​≥0

Use the Two-Stage Method to Solve $x_{1} \geq 0$ And $x_{2} \geq 0$