Use the Two-Stage Method to Solve $z=18 x_{1}+12 x_{2}$ Subject To $2 x_{1}+3x_{2}=24$

Use the two-stage method to solve.
-Maximize $z=18 x_{1}+12 x_{2}$
Subject to: $2 x_{1}+3x_{2}=24$
$2 x_{1}+ x_{2} \leq 45$
$2 \mathrm{x}_{1}+3 \mathrm{x}_{2} \geq 20$
$\mathrm{x}_{1} \geq 0, \mathrm{x}_{2} \geq 0$

A) Maximum is 216 for $x_{1}=0, x_{2}=8$
B) Maximum is 216 for $\mathrm{x}_{1}=12, \mathrm{x}_{2}=0$
C) Maximum is 186 for $x_{1}=9, x_{2}=2$
D) Maximum is 156 for $x_{1}=6, x_{2}=4$