Solve the problem, rounding the answer as appropriate. Assume that "pure dominant" describes one who has twodominant genes for a given trait; "pure recessive" describes one who has two recessive genes for a given trait; and"hybrid" describes one who has one of each.
-In a population, $50 \%$ of females are pure dominant, $40 \%$ are hybrid, and $10 \%$ are pure recessive. If a pure recessive male mates with a random female and their first offspring has the dominant trait, what is the probability that the female is pure dominant?
A) .50
B) .75
C) .56
D) .34

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The Answer of Solve the problem, rounding the answer as appropriate. Assume that "pure dominant" describes one who has twodominant genes for a given trait; "pure recessive" describes one who has two recessive genes for a given trait; and"hybrid" describes one who has one of each.
-In a population, $50 \%$ of females are pure dominant, $40 \%$ are hybrid, and $10 \%$ are pure recessive. If a pure recessive male mates with a random female and their first offspring has the dominant trait, what is the probability that the female is pure dominant?
A) .50
B) .75
C) .56
D) .34

Solve the Problem, Rounding the Answer as Appropriate 50%50 \%50% Of Females Are Pure Dominant

Solve the Problem, Rounding the Answer as Appropriate $50 \%$ Of Females Are Pure Dominant