Assume that two marbles are drawn without replacement from a box with 1 blue, 3 white, 2 green, and 2 red marbles. Find the probability of the indicated result.
-One marble is white, and one marble is blue.
A) $\frac{1}{4}$
B) $\frac{1}{2}$
C) $\frac{3}{56}$
D) $\frac{3}{28}$

Question

Quizplus · Accepted Answer

The probability of drawing one white and one blue marble is calculated by finding the number of favorable outcomes divided by the total number of outcomes. There are 3 ways to choose a white marble and 1 way to choose a blue marble. The total number of ways to draw 2 marbles from 8 is $\binom{8}{2} = 28$. Thus, the probability is $\frac{3 \times 1}{28} = \frac{3}{28}$.

Assume That Two Marbles Are Drawn Without Replacement from a Box