Find the probability.
-A basketball player hits her shot $42 \%$ of the time. If she takes four shots during a game, what is the probability that she misses the first shot and hits the last three? Express the answer as a percentage, and round to the nearest tenth (if necessary).
A) $4.3 \%$
B) $3.1 \%$
C) $31.1 \%$
D) $43 \%$

Question

Quizplus · Accepted Answer

The probability of missing the first shot is $1 - 0.42 = 0.58$. The probability of hitting the last three shots is $0.42^3 = 0.074$. The probability of missing the first shot and hitting the last three shots is $0.58 \times 0.074 = 0.043$. This is equal to $4.3\%$.

Find the Probability 42%42 \%42% Of the Time 4.3%4.3 \%4.3% B) 3.1%3.1 \%3.1%

Find the Probability $42 \%$ Of the Time $4.3 \%$ B) $3.1 \%$