Provide an appropriate response.
-Is $\mathrm{P}\left(\mathrm{R}^{\prime} \mid \mathrm{T}\right)=\frac{\mathrm{P}\left(\mathrm{R}^{\prime}\right) \cdot \mathrm{P}\left(\mathrm{T} \mid \mathrm{R}^{\prime}\right)}{\mathrm{P}(\mathrm{R}) \cdot \mathrm{P}(\mathrm{T} \mid \mathrm{R})+\mathrm{P}\left(\mathrm{R}^{\prime}\right) \cdot \mathrm{P}\left(\mathrm{T} \mid \mathrm{R}^{\prime}\right)}$
a valid alternative form of Bayes' theorem (special case)?

Question

Quizplus · Accepted Answer

This expression is a valid form of Bayes' theorem for the probability of $\mathrm{R}^{\prime}$ given $\mathrm{T}$, using the law of total probability in the denominator.

Provide an Appropriate Response A Valid Alternative Form of Bayes' Theorem (Special Case)